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PERMUTATION AND COMBINATIONS

PERMUTATION AND COMBINATIONS

Permutation : It is defined as the ways of arranging

 

The number of permutations of n objects taken r at a time is

P
r

n    = n (n-1) (n-2) (n-3)…(n-r+1)

o

n!                             n

 

n

=———– nP

= n! nP

= —- = 1

 

(n – r)!                          n

The factorial

The product of n natural numbers 1,2,3…n is denoted as n! This we read as factors n. Some results are

o! = 1

n! = n(n -1) (n – 2)

Some results of permutation :

  • The total number of permutation of n items all together, when p items are of one type, Q are of second type and r of then third kind and the

n! remaining are of different type is ———

p!q!r!

  • The number of permutations of a different items teken r at a time, when each may be repeated any number of

n(nr – 1) times is ———–

n – 1

  • If there are n objects of which m are like and the remaining (n-m) are differ- ent, then the total number of

n!

permutations are———— –. This is called permutations of like objects.

m!(n – m)!

  • The number of circular permutations of n different objects is n-1! because if there are n! linear permutations there

n!

will be—– = (n-1)! circular permutations.

n

Combinations :

When r objects taken out of n objects then combination of n objects taken r at a time, we write

r

n!              n(n – 1)…(n – r + 1)      nP

C
r

n    = C (n,r) =                     =     =

r!(n -r)!                       r!                                 r!

  • Number of combinations of a different objects taken n at a time
r
r

n!                                            nC                                               n – r + 1                                          nC                                               n

C
o
=
n

n                                                = 1 Similarly nC = 1 =                         =                         =                         =

 

r

n!(n – n)!                                      nC

– 1           r            n 1 C

r – 1              r

 

 

r
  • Value of nCl = nCn

 

r
q
  • The sum of nC

n

+ C

r-1

= n+1C

 

p

(4) nC

= nC

Þ p = q or p+q=n

 

C
r

n                    1        1

r

(5) The ratio of = —— = —- = —–

 

 

r
  • nC
  • nC

n

= C

r+1

= nC

n

P

r

 

= n+1C

r!       rP

 

r                r+1                     r

  • The total number of ways by which to divide n identical objects among r

 

r-1

people when each gets at least one is n-qC

  • The number of ways in which m+n objects can be divided in to two groups m + n

having m and n objects = ——–

m! n!

2
  • The total number of diagouals in a polygon of n sides is nC –

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